使用grep快速去除垃圾数据
curl http://host.xx/file.js | grep -Eo "(http|https)://[a-zA-Z0-9./?=_-]*"*
cat file | grep -Eo "(http|https)://[a-zA-Z0-9./?=_-]*"*
最后更新于
这有帮助吗？
curl http://host.xx/file.js | grep -Eo "(http|https)://[a-zA-Z0-9./?=_-]*"*
cat file | grep -Eo "(http|https)://[a-zA-Z0-9./?=_-]*"*最后更新于
这有帮助吗？